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Figure 29
Pos. 2
: one end of the arm
b
is connected to the shaft of the pinionwhile the other bears aweight corresponding to
a Force
F
. To ensure that the system remains in equilibrium, with the actuator under pressure and theweight not
moving, it is necessary for the two torque forces to remain equal.
F
1
* a
=
F * b
In fact, given that theweight corresponding to the Force
F
must be put inmotion, the torque force of the cylinder
must be greater.
1
2
Fig. 29
Figure 30
Pos. 3
: lifting a component from a low conveyer to a higher conveyer.
Pos. 4
: actuation of a butterfly valve.
Pos. 5
: opening of a swing door.
Pos. 6
: sorting an item to be discarded, the cylinder from its rest position is ready to stop andmove the item to
another direction.
3
4
5
6
Fig. 30
3
78
CAMOZZI
>
CYLINDERS