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CYLINDERS
r
b
ß
C
A
b= r sin (180°- )ß
2
C=2 r - b
2
2
Fs
b
1
r
90°
Fs=Mt : b
1
Mt
3
4
Fig. 22
Figure 23
Pos. 5
: impact of the variationof theangleon the strokeand thecylinder diameter assuming the torque is of 100
Nm
.
Length of the crank
r
= 450
mm
Angle
α
= 120°
Calculate the length of the arm
b
2
:
b
2
=
r
* sin
180° –
β
2
b
2
=450
[mm] * sin
180° – 120°
2
b
2
=
450
[mm] * sin
30°
b
2
=
225
mm
In this position, in order to have 100
Nm
of torquewe need a cylinder that develops a Force:
F
s
=
M
t
F
s
=
100
[Nm]
F
s
=
444
N
b
2
0,225
[m]
the necessary stroke length for the cylinder will be:
r
2
–
b
2
C
=2
450
2
[mm]
– 225
2
[mm]
C
=2
202500 – 50625
C
= 2
C
=
779
mm
Figure 23
Pos. 6
: impact of the variation of the angle on the stroke and the cylinder diameter assuming a torque of 100
Nm
.
Length of the crank
r
= 450
mm
The angle
α
= 150°
Calculate the length of the arm
b
3
:
b
3
=
r
* sin
180° –
β
2
b
3
=450
[mm] * sin
180° – 150°
2
b
3
=450
[mm] * sin
15°
b
3
=
116
mm
In this position, in order to have 100
Nm
of torquewe need a cylinder that develops a Force:
F
s
=
M
t
F
s
=
100
[Nm]
F
s
=
862
N
b
3
0,116
[m]
the necessary stroke length of the cylinder will be:
r
2
–
b
2
C
=2
450
2
[mm]
– 116
2
[mm]
C
= 2
202500 – 13456
C
= 2
C
=
869
mm
3
73
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CYLINDERS