NORTH AMERICAN CYLINDER & ACTUATOR CATALOG - page 399

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SEAL KITS & TECHNICAL DATA
Seal Kits & Technical Data
8
NORTH AMERICAN CYLINDER & ACTUATOR CATALOG
>
Release 8.5
376
Calculation:
Example 6: Inclined impact
Application data:
m
= 10 kg
h
= 0,3 m
S
= 0.015 m
= 30°
C
= 600 cycles/h
v
= √ (2g
.
h) √ (2
.
9,81
.
0,3)
= 2,43 m/s
E
k
= m
.
g
.
h 10
.
9,81
.
0,3
= 29,4 Nm
E
d
= F
.
S = m
.
g
.
sin
α
.
s = 10
.
9,81
.
sin30°
.
0,015
= 10
.
9,81
.
0,5
.
0,015
= 0,7 Nm
E
t
= E
k
+ E
d
= 29,4 + 0,7 = 30,1 Nm
E
tc
= E
t
.
C = 30,1
.
600
= 18060 Nm/h
Me
=
2
Et
=
2
.
30,1
= 10,2 Kg
v
2
2,43
2
a
Calculation:
Example 7: Horizontal mass on conveyer
The adequate shock absorber to use in this case is Mod. SA 0806
according to the technical data, where we find that E
t
(
max)=3 Nm, E
tc
(
max)=7000 Nm/h and Me(max)=6 kg.
The adequate shock absorber to use in this case is Mod. SA 2015 according to the technical
data, where we find that E
t
(
max)=59 Nm, E
tc
(
max)=38000 Nm/h and Me(max)=120 kg.
Application data:
m
= 5 kg
v
= 0,5 m/s
µ
= 0,25
S
= 0.006 m
C
= 3000 cycles/h
E
k
=
mv
2
=
5
.
0,5
2
= 0,63 Nm
2 2
E
d
= F . S = m
.
g
.
µ
.
s = 5
.
9,81
.
0,25
.
0,006
= 0,07 Nm
E
t
= E
k
+ E
d
= 0,63 + 0,07 = 0,7 Nm
E
tc
= E
t
.
C = 0,7
.
3000
= 2100 Nm/h
Me
=
2
E
t
=
2
.
07
= 5,6 Kg
v
2
0,5
2
Example 8: Horizontal rotating door
Application data:
m
= 20 kg
ω
= 2,0 rad/s
T
= 20 Nm
Rs
= 0,8 m
A
= 1,0 m
S
= 0,015 m
C
= 600 cycles/h
ω
Calculation:
l
=
m(4A
2
+ B
2
)
=
20(4
.
1,0
2
+ 0,05
2
)
= 6,67 Kg
.
m
2
12 12
E
k
=
l
ω
2
=
6,67
.
2,0
2
= 13,34 Nm
2 2
θ
=
S
=
0,015
= 0,019 rad
Rs 0,8
E
d
= T
.
θ
= 20
.
0,018
= 0,36 Nm
E
t
= E
k
+ E
d
= 13,34 + 0,36 = 13,7 Nm
E
tc
= E
t
.
C = 13,7
.
600
= 8220 Nm/h
v
=
ω
.
Rs = 2,0
.
0,8
= 1,6 m/s
Me
=
2
E
t
=
2
.
13,7
= 10,7 Kg
v
2
1,6
2
The adequate shock absorber to use in this case is Mod. SA 1412
according to the technical data, where we find that E
t
(
max)=20 Nm,
E
tc
(
max)=33000 Nm/h and Me (max)=40 kg.
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