The company reserves the right to vary models and dimensions without notice.
These products are designed for industrial applications and are not suitable for sale to the general public.
8
Seal Kits & Technical Data
NORTH AMERICAN CYLINDER & ACTUATOR CATALOG
>
Release 8.5
SEAL KITS & TECHNICAL DATA
375
Calculation:
Example 3: Free fall impact
Application data:
h
= 0,35 m
m
= 5 kg
S
= 0.01 m
first hypothesis SA 1210
C
= 1500 cycles/h
v
= √ (2g
.
h) √ (2
.
9,81
.
0,35)
= 2,6 m/s
E
k
= m
.
g
.
h = 5
.
9,81
.
0,35
= 17,2 Nm
Consider the shock absorber with the lowest E
t
but superior to 17.2 Nm:
mod. SA 1412 S=0.012 m
E
d
= F
.
S = m
.
g
.
s = 5
.
9,81
.
0,012
= 0,6 Nm
Et
= E
k
+ E
d
= 17,2 + 0,6 = 17,8 Nm
E
tc
= E
t
.
C = 17,8
.
1500
= 26700 Nm/h
Me
=
2
E
t
=
2
.
17,5
= 5 Kg
v
2
2,6
2
Calculation:
Example 4: Vertical impact downwards with propelling force
The adequate shock absorber to use in this case is Mod. SA 2725 according to the technical
data, where we find that E
t
(
max)=147 Nm,
E
tc
(
max)=72000 Nm/h and Me(max)=270 kg.
The adequate shock absorber to use in this case is Mod. SA 1412 according to the technical
data, where we find that E
t
(
max)=20 Nm,
E
tc
(
max)=33000 Nm/h and Me(max)=40 kg.
Application data:
m
= 50 kg
S
= 0.025 m
P
= 6 bar
D
= 63 mm
C
= 600 cicli/h
v
= 1,0 m/s
Calculation:
Example 5: Vertical impact upwards with propelling force
Application data:
m
= 50 kg
h
= 0.3 m
S
= 0.025 m
First hypothesis Mod. SA 2525
P
= 6 bar =0,6 MPa
D
= 63 mm
C
= 600
cycles/h
v
= 1,0 m/s
E
k
=
mv
2
=
50
.
1
2
= 25 Nm
2 2
Consider the shock absorber with the lowest E
t
but superior to 25 Nm:
mod. SA 2015 S=0.015 m
E
d
= F
.
S = (
D
2
.
π
.
P
.
g/100 – m
.
g)
.
S = (
63
2
.
π
6
.
9,81/100 – 50
.
9,81)
.
0,015
= 20,1 Nm
4
4
E
t
= E
k
+ E
d
= 25 + 20,1 = 45,7 Nm
E
tc
= E
t
.
C = 45,1
.
600
= 27060 Nm/h
Me
=
2
Et
=
2
.
45,7
= 91,4 Kg
v
2
1
2
E
k
=
mv
2
=
50
.
1
2
= 25 Nm
2 2
E
d
= F
.
S = (m
.
g +
D
2
.
π
.
P
.
g/100 )
.
S = (50
.
9,81
+
63
.
π
.
6
.
9,81/100)
.
0,025
= 58,1 Nm
4
4
E
t
= E
k
+ E
d
= 25 + 58,1 = 83,1 Nm
E
tc
= E
t
.
C = 83,1
.
600
= 49860 Nm/h
Me
=
2
Et
=
2
.
84
= 168 Kg
v
2
1
2
The adequate shock absorber to use in this case is Mod. SA 2015 according to the technical
data, where we find that E
t
(
max)=59 Nm, E
tc
(
max)=38000 Nm/h and Me(max)=120 kg.