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Repetitive signals

We analyze the following example with repeated movement of the same cylinders in different Phases.

As an example, we observe the following sequence:

A + / B + / B – / A – / B + / B –

The piston rod/piston of cylinder

B

oscillates repeatedly. The limit switches

a1

and

a0

both operate the main valve

of cylinder

B

in order to execute the positive stroke. The limit switch

b0

in

Phase 3

operates the main valve of

the cylinder

A

to execute the negative stroke

A –

, while in

Phase 6

the limit switch

b0

operates the main valve to

enable the positive stroke

A +

. The movement of cylinder

B +

is a function of the actuation of limit switches

a1

and

a0

, the movements

A +

and

A –

are a function of the limit switch

b0

.

We divide the sequence into groups and determine how many lines and memories are needed.

A + / B + / B – / A – /

B + /

B –

U1 /

U2 /

U3 /

U4

4 lines and 3 memories are required.

Figure 96

Phase 1

:

Line U1

is active, the limit switch

b0

is activated and fed from the compressed air network.

The output signal from the limit switch

b0

fulfils two functions:

• when

b0 AND

Line U1

is TRUE, then the

I.C.

valve has air supply to Start the sequence

A +

• when

b0 AND Line U2

is TRUE, then the movement

A –

is permitted.

U1 * I.C. * b0

=

A +

Phase 2

: the piston rod/piston of cylinder

A

executes its positive stroke, then reaches and actuates the limit switch

a1

whose output through the

OR

function, operates the main valve of cylinder

B

, the piston rod/piston of cylinder

B

executes the positive stroke.

U1 * a1

=

B +

Phase 3

: the piston rod/piston of cylinder

B

actuates the limit switch

b1

whose output signal generates the pilot

signal

S2

, which operates memory valve and charges it over, interrupting

U1

and activating

U2

, the limit switch

a1

is no longer fed with compressed air, this means that the main valve of cylinder

B

(being monostable) returns

to its rest position, the piston rod/piston starts its movement in the negative direction

B –

.

b1

=

S2

=

U2

=

B –

Phase 4

: the limit switch

b0

fulfils the second of the afore-mentioned functions; when

b0 AND U2

is TRUE, then

the movement of the piston rod/piston of cylinder

A

towards the negative position

A –

is enabled.

U2 * b0

=

A –

Phase 5

: the limit switch

a0

is fed by

U2

and with its actuation, the signal

S3

is generated, which operates the

memory valve, interrupting

U2

and activating

U3

. The output of

U3

, via the

OR

function, operates the pilot port

of the monostable valve of cylinder

B

, which by changing over initiates the movement of the piston rod/piston of

cylinder

B

in the positive direction

B +

.

U2 * a0

=

S3

=

U3

=

B +

Phase 6

: when the limit switch

b1

is reached, the following conditions apply; when

b1 AND

Line U3

is TRUE,

then the signal

S4

is generated, which operates the memory valve, interrupting

Line U3

and activating

Line

U4

. Activating

Line U4

, the limit switch

a1

is no longer fed with compressed air which means the main valve of

cylinder

B

(being monostable) returns to its rest position, the piston rod/piston starts its movement in the negative

direction

B –

. When the signal from limit switch

b0 AND

Line U4

is TRUE, the signal

S1

is generated, resetting

the memory cascade.

U3 * b1

=

S4

=

U4

=

B –

5

186

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CIRCUIT TECHNIQUE